`1)``Mg+2HCl->MgCl_2+H_2`
`CuO+2HCl->CuCl_2+H_2O`
`2)``n_{H_2}=(4,48)/(22,4)=0,2(mol)`
`n_{Mg}=n_{H_2}=0,2(mol)`
`m_{Mg}=0,2.24=4,8(g)`
`m_{CuO}=8,8-4,8=4(g)`
`3)``n_{CuO}=4/(64+16)=0,05(mol)`
`n_{HCl}=(0,2.2)+(0,05.2)=0,5(mol)`
`mdd_{HCl}=(0,5.36,5)/(25%)=73(g)`
`Vdd_{HCl}=(73)/(1,12)=65,178(ml)`