g.$-105+x=-2x-75$
⇒$x+2x=-75+105$
⇒ $3x=30$
⇒ $x=10$
Vậy $x=10$
h. $(x-1)^3=2(x-1)^2$
⇒ $(x-1)^3-2(x-1)^2=0$
⇒ $(x-1)^2.(x-1-2)=0$
⇒ $(x-1)^2.(x-3)=0$
⇒ \(\left[ \begin{array}{l}(x-1)^2=0\\x-3=0\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x-1=0\\x=3\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=1\\x=3\end{array} \right.\)
Vậy $x=1$ hoặc $x=3$