\(\left\{ \begin{array}{l}\dfrac{{x + 6}}{{x - 3}} \le 0\\\dfrac{{x + 2}}{{x + 1}} \ge 0\end{array} \right.\)
A.\( - 6 \le x \le 2\)
B.\( - 1 < x < 3\)
C.\(\left[ \begin{array}{l} - 1 < x < 3\\ - 6 \le x \le - 2\end{array} \right.\)
D.\( - 6 \le x < 3\)