Đáp án:
\({C_5}{H_{10}}{O_2}\)
Giải thích các bước giải:
\(\begin{array}{l}
{n_{CaC{O_3}}} = \dfrac{{250}}{{100}} = 2,5\,mol\\
{n_{C{O_2}}} = {n_{CaC{O_3}}} = 2,5\,mol\\
{n_{{H_2}O}} = \dfrac{{45}}{{18}} = 2,5\,mol\\
{n_C} = {n_{C{O_2}}} = 2,5\,mol\\
{n_H} = 2{n_{{H_2}O}} = 5\,mol\\
{m_O} = 51 - 2,5 \times 12 - 5 = 16g\\
{n_O} = \dfrac{{16}}{{16}} = 1\,mol\\
{n_C}:{n_H}:{n_O} = 2,5:5:1 = 5:10:2\\
\Rightarrow CTDGN:{C_5}{H_{10}}{O_2}\\
{M_A} = 25,5 \times 4 = 102g/mol\\
\Rightarrow 102n = 102 \Rightarrow n = 1\\
CTPT:{C_5}{H_{10}}{O_2}
\end{array}\)
