$1/$
$a/$
$V_{H2S}=0,14.22,4=3,136l$
$b/$
$V_{NH3}=2,4.22,4=53,76l$
$c/$
$nSO2=12,8/64=0,2mol$
$V_{SO2}=0,2.22,4=4,48l$
$d/$
$nCO2=22/44=0,5mol$
$V_{CO2}=0,5.22,4=11,2l$
$2/$
$a/$
$\%m_{Na}=100\%-60,68\%=39,32\%$
$m_{Na}=58,5.39,32\%=23g$
$⇒n_{Na}=23/23=1mol$
$m_{Cl}=58,5.60,68\%=35,5g$
$⇒n_{Cl}=35,5/35,5=1mol$
Vậy $CTHH$ của A là $NaCl$
$b/$
$m_{Na}=43,4\%.106=46g$
$⇒n_{Na}=46/23=2mol$
$m_{C}=11,3\%.106=12g$
$⇒n_{C}=12/12=1mol$
$m_{O}=45,3\%.106=48g$
$⇒n_{O}=48/16=3mol$
Vậy CTHH của B là $Na_{2}CO_{3}$
