Đáp án:
\({V_{hh}} = 96,32{\text{ lít}}\)
\({m_{hh}} = 124,8{\text{ gam}}\)
Giải thích các bước giải:
Ta có:
\({n_{{H_2}}} = \frac{{{{1,2.10}^{23}}}}{{{{6.10}^{23}}}} = 0,2{\text{ mol}}\)
\({n_{S{O_2}}} = \frac{{6,4}}{{64}} = 0,1{\text{ mol}}\)
\( \to {n_{hh}} = {n_{{O_2}}} + {n_{{N_2}}} + {n_{{H_2}}} + {n_{S{O_2}}}\)
\( = 1,5 + 2,5 + 0,2 + 0,1 = 4,3{\text{ mol}}\)
\( \to {V_{hh}} = 4,3.22,4 = 96,32{\text{ lít}}\)
\( \to {m_{hh}} = {m_{{O_2}}} + {m_{{N_2}}} + {m_{{H_2}}} + {m_{S{O_2}}}\)
\( = 1,5.32 + 2,5.28 + 0,2.2 + 6,4 = 124,8{\text{ gam}}\)