Đáp án:
\(\begin{array}{l}
a.\\
{U_2} = 44V\\
b.\\
{b_1}.\\
{N_2} = \frac{{2500}}{{11}}\\
{b_2}.\\
{N_1} = 880
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a.\\
\frac{{{N_2}}}{{{N_1}}} = \frac{{{U_2}}}{{{U_1}}}\\
\frac{{200}}{{1000}} = \frac{{{U_2}}}{{220}}\\
{U_2} = 44V\\
b.\\
{b_1}.\\
\frac{{{N_2}}}{{{N_1}}} = \frac{{{U_2}}}{{{U_1}}}\\
\frac{{{N_2}}}{{1000}} = \frac{{44 + 6}}{{220}}\\
{N_2} = \frac{{2500}}{{11}}\\
{b_2}.\\
\frac{{{N_2}}}{{{N_1}}} = \frac{{{U_2}}}{{{U_1}}}\\
\frac{{200}}{{{N_1}}} = \frac{{44 + 6}}{{220}}\\
{N_1} = 880
\end{array}\)