Đáp án:
$\begin{array}{l}
DKxd:x \ne 2;x \ne 0\\
P = \frac{{{x^2}}}{{x - 2}}.\left( {\frac{{{x^2} + 4}}{x} - x} \right) + 3\\
= \frac{{{x^2}}}{{x - 2}}.\frac{{{x^2} + 4 - {x^2}}}{x} + 3\\
= \frac{{{x^2}}}{{x - 2}}.\frac{4}{x} + 3\\
= \frac{{4x}}{{x - 2}} + 3\\
= \frac{{4x + 3x - 6}}{{x - 2}}\\
= \frac{{7x - 6}}{{x - 2}}
\end{array}$