Đáp án+Giải thích các bước giải:
\(e)2xy+3z+6y+zx\\=x(2y+z)+3(2y+z)=(2y+z)(x+3)\\f)5x^2+5xy-x-y\\=5x(x+y)-(x+y)\\=(x+y)(5x-1)\\g)2x^2-2xy-7x+7y\\=2x(x-y)-7(x-y)\\=(x-y)(2x-7)\\h)5x^2-5y^2\\=5(x^2-y^2)\\=5(x-y)(x+y)\\i)3x^3+6x^2y+3xy^2\\=3xy(x^2+2xy+y^2)\\=3xy(x+y)^2\\j)x^2-2x-4y^2-4y\\=x^2+4xy+4y^2-2x-4y-4xy-8y^2\\=(x+2y)^2-2(x+2y)-4y(x+2y)\\=(x+2y)(x+2y-2-4y)\\=(x+2y)(x-2y-2)\\k)27y^3-3y\\=3y(9y^2-1)\\=3y(3y-1)(3y+1)\\l)5(x-2)^2-5x+10\\=5[(x-2)^2-x+2]\\=5[(x-2)^2-(x-2)\\=5(x-2)(x-3)\)
