b) \(\dfrac{3}{4}xy+\dfrac{3}{4}x^2y-\dfrac{3}{4}xy^2\Leftrightarrow\dfrac{3}{4}xy+\dfrac{3}{4}xy\left(x-y\right)\Leftrightarrow\dfrac{3}{4}xy\left(x-y+1\right)\)

c) \(x\left(x-2\right)+y\left(2-x\right)\Leftrightarrow x\left(x-2\right)-y\left(x-2\right)=\left(x-y\right)\left(x-2\right)\)

d) \(x\left(3-2x\right)+6-4x\Leftrightarrow x\left(3-2x\right)+2\left(3-2x\right)\Leftrightarrow\left(x+2\right)\left(3-2x\right)\)

Phân tich đa Thức thành nhân tử.

a,3xy +5xy mũ 2-xy mũ 2

b,x(y-x)+3(y-x)

a)\(3xy+5xy^2-xy^2\)

\(=3xy+4xy^2=xy\left(4y+3\right)\)

b)\(x\left(y-x\right)+3\left(y-x\right)\)

\(=\left(x+3\right)\left(y-x\right)\)

Phân tích thành nhân tử :

x(x+y)-5x-5y

\(x\left(x+y\right)-5x-5y\)

\(=x\left(x+y\right)-\left(5x+5y\right)\)

\(=x\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x-5\right)\left(x+y\right)\)

1,phân tích đa thức thành nhân tử chung

\(x^3-1+5x^2-5+3x-3\)

x3-1=(x-1)(x2+x+1)

5x2-5=5(x2-1)=5(x-1)(x+1)

3x-3=3(x-1)

Biểu thức=(x-1)(x2+x+1+5x+5+3)=(x-1)(x2+6x+9)=(x-1)(x+3)2