Phương trình \({3 \over {{{\cos }^2}x}} - 4\tan x - 2 = 0\)
A.\(\left[ \matrix{x = \pm {\pi \over 4} + k\pi \hfill \cr x = \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
B.\(\left[ \matrix{x = {\pi \over 4} + k2\pi \hfill \cr x = \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
C.\(\left[ \matrix{x = {\pi \over 4} + k\pi \hfill \cr x = \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
D.\(\left[ \matrix{x = - {\pi \over 4} + k\pi \hfill \cr x = - \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
A.\(\left[ \matrix{x = \pm {\pi \over 4} + k\pi \hfill \cr x = \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
B.\(\left[ \matrix{x = {\pi \over 4} + k2\pi \hfill \cr x = \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
C.\(\left[ \matrix{x = {\pi \over 4} + k\pi \hfill \cr x = \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
D.\(\left[ \matrix{x = - {\pi \over 4} + k\pi \hfill \cr x = - \arctan {1 \over 3} + k\pi \hfill \cr} \right.\,\,\,\left( {k \in Z} \right)\)
Loga
Hóa Học lớp 12
