`\sqrt{x+1}+5\sqrt{4x+4}-\sqrt{25x+25}=24` ĐKXĐ: `x\geq-1`
`<=>\sqrt{x+1}+5\sqrt{4(x+1)}-\sqrt{25(x+1)}=24`
`<=>\sqrt{x+1}+10\sqrt{x+1}-5\sqrt{x+1}=24`
`<=>6\sqrt{x+1}=24`
`<=>\sqrt{x+1}=4`
`<=>(\sqrt{x+1})^2=4^2`
`<=>x+1=16`
`<=>x=15` `(TMĐK)`
Vậy `x=15`.