A.\(\sqrt 6 \)
B.\(\dfrac{{\sqrt 6 }}{2}\)
C.\(\dfrac{1}{{\sqrt 6 }}\)
D.\(\sqrt 2 \)

A.\( - 3\)
B.\(1\)
C.\(3\)
D.\(0\)

A.\(I\left( { - 1;2; - 3} \right),\,\,R = 16\)
B.\(I\left( { - 1;2; - 3} \right),\,\,R = 4\)
C.\(I\left( {1; - 2;3} \right),\,\,R = 4\)
D.\(I\left( {1; - 2;3} \right),\,\,R = 16\)

A.\(C_7^3\)
B.\(6\)
C.\(A_7^3\)
D.\(36\)

A.\(10\)
B.\(5\)
C.\(\sqrt {10} \)
D.\(5\sqrt 2 \)

A.\(y = 2\)
B.\(x =  - 2\)
C.\(y =  - 2\)
D.\(x = 1\)

A.\(1 + i\)
B.\(5 - 5i\)
C.\(5 - 2i\)
D.\(5 + 4i\)

A.\(x = 1\)
B.\(x = 3\)
C.\(x =  - 1\)
D.\(x = 2\)

A.\(0\)
B.\(1\)
C.\(2\)
D.\(4\)

A.\(\dfrac{{x + 3}}{2} = \dfrac{{y + 2}}{2} = \dfrac{{z - 1}}{{ - 1}}\)
B.\(\dfrac{{x + 3}}{{ - 2}} = \dfrac{{y + 2}}{2} = \dfrac{{z - 1}}{1}\)
C.\(\dfrac{{x + 3}}{2} = \dfrac{{y - 2}}{{ - 2}} = \dfrac{{z - 1}}{{ - 1}}\)
D.\(\dfrac{{x - 3}}{2} = \dfrac{{y + 2}}{{ - 2}} = \dfrac{{z - 1}}{{ - 1}}\)