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hoangnguyenthanhluan005
2 năm trước
$\text{cho a,b,c > 0 thoả mãn ab+bc+ca=2abc. Chứng minh rằng : }$ $\dfrac{1}{a(2a-1)^2}$ + $\dfrac{1}{b(2b-1)^2}$ + $/dfrac{1}{c(2c-1)^2}$ $\ge$ $\dfrac{1}{2}$
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