Đáp án:
Giải thích các bước giải:
$1/$
$C_M = \dfrac{10D.C\%}{M}$
$2/$
$C_M = \dfrac{S.1000D}{M.(S+100)}$
$3/$
$C\% = \dfrac{S}{S+100}.100\%$
$a/$
$C\%_{HNO_3} = \dfrac{M.C_M}{10D} = \dfrac{63.4,97}{10.1,137}.100\% = 27,53\%$
$b/$
$C_{M_{HCl}} = \dfrac{10.1,19.37}{36,5} = 12,06M$
$c/$
$C\% = \dfrac{S}{S+100}.100\% = \dfrac{36}{100+36}.100\% = 26,47\%$
$d/$
$C\% = \dfrac{S}{S+100}.100\%$
$⇔ \dfrac{44,44}{100} = \dfrac{S}{S+100}$
$⇔ S = 80(gam)$