$\dfrac{3}{2x}+\dfrac{3x-3}{2x-1}+\dfrac{2x^2+1}{4x^2-2x}$ ĐKXĐ: $x\neq0;\dfrac{1}{2}$
$=\dfrac{3(2x-1)+2x(3x-3)+2x^2+1}{4x^2-2x}$
$=\dfrac{6x-3+6x^2-6x+2x^2+1}{2x(2x-1)}$
$=\dfrac{8x^2-2}{2x(2x-1)}$
$=\dfrac{2(4x^2-1)}{2x(2x-1)}$
$=\dfrac{2(2x-1)(2x+1)}{2x(2x-1)}$
$=\dfrac{2x+1}{x}$