Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
ĐK:x \ne \pm \frac{1}{2}\\
\frac{{10}}{{2x + 1}} - \frac{{10x - 5}}{{4x}}.\left( {\frac{{2x + 1}}{{2x - 1}} - \frac{{2x - 1}}{{2x + 1}}} \right)\\
= \frac{{10}}{{2x + 1}} - \frac{{10x - 5}}{{4x}}.\frac{{4{x^2} + 4x + 1 - 4{x^2} + 4x - 1}}{{\left( {2x - 1} \right)\left( {2x + 1} \right)}}\\
= \frac{{10}}{{2x + 1}} - \frac{{5\left( {2x - 1} \right)}}{{4x}}.\frac{{8x}}{{\left( {2x - 1} \right)\left( {2x + 1} \right)}}\\
= \frac{{10}}{{2x + 1}} - \frac{{10}}{{2x + 1}} = 0
\end{array}\)
