Giải thích các bước giải:
\(\overline M=\dfrac{1.28+3.2}{1+3}=8,5\ g/mol\)
\(\to d_{hh/O_2}=\dfrac{8,5}{32}=\dfrac{17}{64}\)
\(n_{hh}=\dfrac{29,12}{22,4}=1,3\ mol\)
\(\to n_{N_2}+n_{H_2}=1,3\)
mà \(n_{N_2}:n_{H_2}=1:3\)
\(
to 3n_{N_2}-n_{H_2}=0\)
\(\to n_{N_2}=0,325\ mol; n_{H_2}=0,975\ mol\)
\(\to \%V_{N_2}=\dfrac{0,325}{1,3}\cdot 100\%=25\%\to \%V_{H_2}=75\%\)
\(\%m_{N_2}=\dfrac{0,325.28}{8,5.1,3}=82,35\%\to \%m_{H_2}=17,65\%\)