Tích phân $\int\limits_{0}^{1}{{{{x}^{5}}{{{(1-{{x}^{3}})}}^{6}}dx}}$ bằng? A. $\frac{1}{{56.}}$ B. $\frac{1}{{84}}.$ C. $\frac{1}{{168}}.$ D. $\frac{1}{{42}}.$
Đáp án đúng: C Đặt $t=1-{{x}^{3}}=>dt=-3{{x}^{2}}dx=>I=\frac{1}{3}\int\limits_{0}^{1}{{{{t}^{6}}(1-t)dt=\frac{1}{3}\left. {\left( {\frac{{{{t}^{7}}}}{7}-\frac{{{{t}^{8}}}}{8}} \right)} \right|}}_{0}^{1}=\frac{1}{{168}}.$