Đáp án:
Giải thích các bước giải:
`\color{blue}{a,}(-x-155)-45=-100`
`⇔ -x-155-45=-100`
`⇔-x-200=-100`
`⇔-x=-100+200`
`⇔-x=100`
`⇔x=-100`
,
`\color{red}{b,}-48-|-x+3|=-60`
`⇔-|-x+3|=-60+48`
`⇔-|-x+3|=-12`
`⇔|-x+3|=12`
\(⇔\left[ \begin{array}{l}-x+3=12\\-x+3=-12\end{array} \right.\)
\(⇔\left[ \begin{array}{l}-x=12-3\\-x=-12-3\end{array} \right.\)
\(⇔\left[ \begin{array}{l}-x=9\\-x=-15\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=-9\\x=15\end{array} \right.\)
Vậy `x=-9` hoặc `x=15`
,
`\color{green}{c,}(-2x-4)(-4x+16)=0`
\(⇔\left[ \begin{array}{l}-2x-4=0\\-4x+16=0\end{array} \right.\)
\(⇔\left[ \begin{array}{l}-2x=4\\-4x=-16\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=4:(-2)\\x=-16:(-4)\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=-2\\x=4\end{array} \right.\)
Vậy `x=-2` hoặc `x=4`
