Đáp án:
a, (x-2)²-9=0
⇔ (x-2)² - 3² =0
⇔(x-2-3)(x-2+3)=0
⇔(x-5)(x+1)=0
⇔\(\left[ \begin{array}{l}x-5=0\\x+1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=5\\x=-1\end{array} \right.\)
b, x²-6x=7
⇔x²-6x-7=0
⇔ x²-7x+x-7=0
⇔x(x-7)+(x-7)=0
⇔(x-7)(x+1)=0
⇔\(\left[ \begin{array}{l}x-7=0\\x+1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=7\\x=-1\end{array} \right.\)
c, x²+4x=-4
⇔x²+4x+4=0
⇔(x+2)²=0
⇔x+2=0
⇔ x=-2