ta có : \(x^3+3x^2+3x+2=0\Leftrightarrow x^3+2x^2+x^2+2x+x+2=0\)
\(\)\(\Leftrightarrow x^2\left(x+2\right)+x\left(x+2\right)+\left(x+2\right)=0\Leftrightarrow\left(x+2\right)\left(x^2+x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=0\\x^2+x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x\in\varnothing\end{matrix}\right.\) vậy \(x=-2\)
