\(\left(3x-5\right).2x+\left(3x-5\right).4=0\)
\(\Leftrightarrow\left(3x-5\right)\left(2x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-5=0\\2x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=5\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{\dfrac{5}{3};-2\right\}\)
