Giải thích các bước giải:
\(\begin{array}{l}
\left| {x + 1} \right| + \left| {x - 2} \right| + \left| {x + 3} \right| = 6\\
\to \left[ \begin{array}{l}
x + 1 + x - 2 + x + 3 = 6\\
x + 1 + x - 2 + x + 3 = - 6\\
- x - 1 + x - 2 + x + 3 = 6\\
x + 1 - x + 2 + x + 3 = 6\\
x + 1 + x - 2 - x - 3 = 6\\
- x - 1 - x + 2 + x + 3 = 6\\
- x - 1 + x - 2 - x - 3 = 6\\
x + 1 - x + 2 - x - 3 = 6
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \frac{4}{3}\\
x = - \frac{8}{3}\\
x = 6\\
x = 0\\
x = 10\\
x = - 2\\
x = - 12\\
x = - 6
\end{array} \right.
\end{array}\)
