\(6x^2-18x=0\)
\(\Leftrightarrow6x\left(3-x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}6x=0\\3-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0:6\\x=3-0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
Vậy x=0 và x=3
