Đáp án đúng: D
Giải chi tiết:\(\begin{array}{l}65 - {4^{x + 2}} = {2014^0}\\65 - {4^{x + 2}} = 1\\\,\,\,\,\,\,\,\,\,\,\,{4^{x + 2}} = 65 - 1\\\,\,\,\,\,\,\,\,\,\,\,{4^{x + 2}} = 64\\\,\,\,\,\,\,\,\,\,\,\,{4^{x + 2}} = {4^3}\\\,\,\,\,\,\,\,\,\,x + 2 = 3\\\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\, = 3 - 2 = 1.\end{array}\)
Chọn D