`a)`
` \sqrt(2x)+ 2 \sqrt(x+5)` xác định khi
` 2x \ge 0;\ x +5 \ge 0`
`\to x \ge 0;\ x \ge -5`
`\to x \ge 0`
Vậy ĐKXĐ : ` x \ ge 0`
`b)`
` B = ( \sqrt(3) -1)^2 + ( \sqrt(24) - 2\sqrt(3))/(\sqrt(2) -1)`
` = 3 - 2\sqrt(3) +1 + ( 2\sqrt(6) - 2\sqrt(3))/(\sqrt(2) -1)`
`= 4 - 2\sqrt(3) + ( 2 \sqrt(3) . ( \sqrt(2) -1))/(\sqrt(2) -1)`
` = 4 - 2\sqrt(3) + 2 \sqrt(3) `
` = 4`