Đáp án đúng: B Đặt z = x + yi. Khi đó: $\begin{array}{l}(2-i)z+3-2i=\overline{z}(i+1)\Leftrightarrow (2-i)(x+yi)+3-2i=(x+yi)(i+1)\\\Leftrightarrow \left\{ \begin{array}{l}x=-3\\y=-\frac{4}{3}\end{array} \right.\Rightarrow z=-3-\frac{4}{3}i\Rightarrow |z|=\sqrt{{{{{(-3)}}^{2}}+{{{\left( {-\frac{4}{3}} \right)}}^{2}}}}=\frac{{\sqrt{{97}}}}{3}\end{array}$