Đáp án + giải thích các bước giải:
a) `5x^2-x=0`
`->x(5x-1)=0`
`->`\(\left[ \begin{array}{l}x=0\\5x-1=0\end{array} \right.\)
`->`\(\left[ \begin{array}{l}x=0\\x=\dfrac{1}{5}\end{array} \right.\)
Vậy `x=0;1/5`
b) `x^2-2x=0`
`->x(x-2)=0`
`->`\(\left[ \begin{array}{l}x=0\\x-2=0\end{array} \right.\)
`->`\(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\)
Vậy `x=0;2`
c) `x^2-3x=0`
`->x(x-3)=0`
`->`\(\left[ \begin{array}{l}x=0\\x-3=0\end{array} \right.\)
`->`\(\left[ \begin{array}{l}x=0\\x=3\end{array} \right.\)
Vậy `x=0;3`
d) `3x^2-4x=0`
`->x(3x-4)=0`
`->`\(\left[ \begin{array}{l}x=0\\3x-4=0\end{array} \right.\)
`->`\(\left[ \begin{array}{l}x=0\\x=\dfrac{4}{3}\end{array} \right.\)
Vậy `x=0;4/3`
