Đáp án đúng: C
Giải chi tiết:\(\eqalign{& a)\,\,121 - 2\left( {x + 6} \right) = \left| { - 11} \right|{.2016^0} \cr & \,\,\,\,\,\,\,121 - 2\left( {x + 6} \right) = 11.1 = 11 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\left( {x + 6} \right) = 121 - 11 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\left( {x + 6} \right) = 110 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x + 6 = 110:2 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\, = 55 - 6 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\, = 49. \cr} \)
\(\eqalign{& b)\,\,2.\left| {x - 1} \right| - \left( { - 3} \right) = {3^{2017}}:{3^{2016}} \cr & \,\,\,\,\,\,\,2.\left| {x - 1} \right| + 3 = 3 \cr & \,\,\,\,\,\,\,2.\left| {x - 1} \right|\,\,\,\,\,\,\,\,\,\,\, = 3 - 2 \cr & \,\,\,\,\,\,\,\,\,\,\,\left| {x - 1} \right|\,\,\,\,\,\,\,\,\,\,\,\, = 0 \cr & \,\,\,\,\,\,\,\,\,\,\,\,x - 1\,\,\,\,\,\,\,\,\,\,\,\,\, = 0 \cr & \,\,\,\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 1. \cr} \)
