Đáp án:
Ta cóa:
`3x = 2y ; 7y = 5z`
`-> x/2 = y/3 ; y/5 = z/7`
`-> x/10 = y/15 ; y/15 = z/21`
`-> x/10 = y/15 = z/21`
`= (x-y+z)/(10-15+21) = 32/16 = 2`
`-> `
$\left\{\begin{matrix}x=2.10=20& \\y=2.15=30&\\ z=2.21=42& \end{matrix}\right.$
Vậy `(x,y,z)=(20,30,42`