Đáp án + Giải thích các bước giải:
d, `(2x - 3)^8 = (2x - 3)^6`
`=> (2x - 3)^8 - (2x - 3)^6 = 0`
`=> (2x - 3)^6 . ( (2x - 3)^2 - 1) = 0`
`=> (2x - 3)^6 = 0` hoặc `(2x - 3)^2 - 1 = 0`
Nếu `(2x - 3)^6 = 0` ; Nếu `(2x - 3)^2 - 1 = 0`
`=> 2x - 3 = 0` ; `(2x - 3)^2 = 1`
`=> 2x = 0 + 3` ; \(\left[ \begin{array}{l}2x - 3 = 1\\2x - 3 = -1\end{array} \right.\)
`=> 2x = 3` ; \(\left[ \begin{array}{l}2x = 4\\2x = 2\end{array} \right.\)
`=> x = 3/2` ; \(\left[ \begin{array}{l}x = 2\\x = 1\end{array} \right.\)
Vậy `x \in {3/2 ; 2 ; 1}`
