Đáp án:
\(\frac{{10{x^2} + 10}}{{{{(x - 1)}^2}{{(x + 1)}^2}}}\)
Giải thích các bước giải:
\(\begin{array}{l}
\frac{{3x + 2}}{{{x^2} - 2x + 1}} - \frac{6}{{{x^2} - 1}} - \frac{{3x - 2}}{{{x^2} + 2x + 1}}(x \ne 1, - 1)\\
= \frac{{(3x + 2){{(x + 1)}^2} - 6({x^2} - 1) - (3x - 2){{(x - 1)}^2}}}{{{{(x - 1)}^2}{{(x + 1)}^2}}}\\
= \frac{{10{x^2} + 10}}{{{{(x - 1)}^2}{{(x + 1)}^2}}}
\end{array}\)
