Tính A=(3x^3+8x^2+2)^1998
1)x= \(\dfrac{\left(\sqrt{5}+2\right)\sqrt[3]{17\sqrt{5}-38}}{\sqrt{5}+\sqrt{14-6\sqrt{5}}}\)
Tính A=\(\left(3x^3+8x^2+2\right)^{1998}\)
2)x=\(\dfrac{1}{\sqrt[3]{4-\sqrt{15}}}+\sqrt[3]{4-\sqrt{15}}\)
tính B=\(x^3-3z+1987\)