`A=y^2-1/2y+1/16`
`A=y^2-2.y. 1/4+(1/4)^2`
`A=(y-1/4)^2`
Thay `y=100` vào A ta có:
`A=(100-1/4)^2=(399/4)^2=159201/16`
Vậy `A=159201/16` khi `y=100`
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`B=4x^2-9y^2-6y-1`
`B=(2x)^2-(3y+1)^2`
`B=(2x-3y-1)(2x+3y+1)`
Thay `x=23;y=1` vào B ta có:
`B=(2.23-3.1-1)(2.23+3.1+1)`
`B=(46-3-1)(46+3+1)`
`B=42.50`
`B=2100`
Vậy `B=2100` khi `x=23;y=1`
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`C=x^2-8x-y^2+2y+17`
`C=(x^2-8x+16)-(y^2-2y+1)+2`
`C=(x-4)^2-(y-1)^2+2`
Thay `x=54;y=31` vào C ta có:
`C=(54-4)^2-(31-1)^2+2`
`C=50^2-30^2+2`
`C=2500-900+2`
`C=1602`
Vậy `C=1602` khi `x=54;y=31`.