Tính giới hạn hàm số :
\(\lim\limits_{x\rightarrow0}\frac{\ln\left(1+2x\right)}{\tan x}\)
\(L=\lim\limits_{x\rightarrow0}\frac{\ln x-1}{\tan x}=\lim\limits_{x\rightarrow0}\frac{\ln\left(1+2x\right)}{\frac{\sin x}{\cos x}}=\lim\limits_{x\rightarrow0}\frac{\ln\left(1+2x\right)}{2x.\frac{\sin x}{x}.\frac{1}{2\cos x}}\)
\(=\lim\limits_{x\rightarrow0}\left[\frac{\ln\left(1+2x\right)}{2x}.\frac{1}{\frac{\sin x}{x}}.2\cos x\right]=1.\frac{1}{1}.2.1=2\)
\(\lim\limits_{x\rightarrow0}\frac{e^x-1}{\sqrt{x+1}-1}\)
\(\lim\limits_{x\rightarrow0}\frac{e^{5x+3}-e^3}{2x}\)
\(\lim\limits_{x\rightarrow0}\frac{\ln\left(1+x^3\right)}{2x}\)
\(\lim\limits_{x\rightarrow0}\frac{e^x-e^{-x}}{\sin x}\)
\(\lim\limits_{x\rightarrow+\infty}\left(\frac{x}{1+x}\right)^x\)
\(\lim\limits_{x\rightarrow+\infty}\left(\frac{x+1}{x-2}\right)^{2x-1}\)
\(\lim\limits_{x\rightarrow e}\frac{\ln x-1}{x-e}\)
tính Lim(x-->0)\(\frac{1}{\sqrt[3]{\left(x+1\right)^2+\sqrt[3]{x+1}+1}}\)
Cho \(y=\sin\left(\ln x\right)+\cos\left(\ln x\right)\). Chứng minh hệ thức : \(y+xy'+x^2y"=0\)
Cho \(y=x\sin x\). Chứng minh hệ thức :
\(xy=2\left(y'-\sin x\right)+xy"=0\)
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