a)
Phản ứng xảy ra:
\({N_2}{O_5} + {H_2}O\xrightarrow{{}}2HN{O_3}\)
Ta có:
\({n_{{N_2}{O_5}}} = \frac{{4,32}}{{14.2 + 16.5}} = 0,04{\text{ mol}}\)
\( \to {n_{HN{O_3}}} = 2{n_{{N_2}{O_5}}} = 0,08{\text{ mol}}\)
\( \to {C_{M{\text{ HN}}{{\text{O}}_3}}} = \frac{{0,08}}{{0,2}} = 0,4M = [{H^ + }] = [N{O_3}^ - ]\)
b)
Phản ứng xảy ra:
\(N{a_2}O + {H_2}O\xrightarrow{{}}2NaOH\)
Ta có:
\({n_{N{a_2}O}} = \frac{{15,5}}{{23.2 + 16}} = 0,25{\text{ mol}}\)
\( \to {n_{NaOH}} = 2{n_{N{a_2}O}} = 0,5{\text{ mol}}\)
\( \to {C_{M{\text{ NaOH}}}} = \frac{{0,5}}{{0,4}} = 1,25{\text{ M = [N}}{{\text{a}}^ + }] = [O{H^ - }]\)
