Đáp án:
$5 + 2 \sqrt2 + 2 \sqrt{3} + 2 \sqrt6$
Giải thích các bước giải:
$\left(\dfrac{3+2\sqrt{3}}{\sqrt{3}}+\dfrac{2+\sqrt{2}}{\sqrt{2}+1}\right).\left(1:\dfrac{1}{\sqrt{2}+\sqrt{3}}\right)\\ =\left(\dfrac{\sqrt{3}(\sqrt{3}+2)}{\sqrt{3}}+\dfrac{\sqrt{2}(\sqrt{2}+1)}{\sqrt{2}+1}\right).\left(\sqrt{2}+\sqrt{3}\right)\\ =\left(\sqrt{3}+2+\sqrt{2}\right).\left(\sqrt{2}+\sqrt{3}\right)\\ =5 + 2 \sqrt2 + 2 \sqrt{3} + 2 \sqrt6$