`2HCl+Na_2CO_3->2NaCl+H_2O+CO_2↑`
`n_{HCl}=0,1.2=0,2(mol)`
`n_{Na_2CO_3}=0,5n_{HCl}=0,1(mol)`
`x=C_{M_{ddNa_2CO_3}}=(0,1)/(0,05)=2(M)`
`V_{ddspư}=0,1+0,05=0,15(l)`
`n_{NaCl}=n_{HCl}=0,2(mol)`
`y=C_{M_{ddNaCl}}=(0,2)/(0,15)=1,333(M)`
`\text{___________________________________}`
Đáp án:
`x=2(M)`
`y=1,333(M)`