`\qquad x^2+6x-3=4x\sqrt{2x-1}`
Trừ hai vế của phương trình cho $4x^2$ ta có:
`\qquad x^2+6x-3-4x^2=4x\sqrt{2x-1}-4x^2`
`<=>-3x^2+6x-3=-4x(x-\sqrt{2x-1})`
`<=>-3(x^2-2x+1)=-4x(x-\sqrt{2x-1})`
`<=>3(x-1)^2=4x(x-\sqrt{2x-1})`
`<=>4x(x-\sqrt{2x-1})=3(x-1)^2`
`<=>4x . {(x-\sqrt{2x-1})(x+\sqrt{2x-1})}/{x+\sqrt{2x-1}}=3(x-1)^2`
`<=>4x. {x^2-(2x-1)}/{x+\sqrt{2x-1}}=3(x-1)^2`
`<=>{4x (x-1)^2}/{x+\sqrt{2x-1}}=3(x-1)^2`
