$m_{HCl}=200.14,6\%=29,2g$
$⇒n_{HCl}=29,2/36,5=0,8mol$
$PTHH : Zn+2HCl\to ZnCl_2+H_2↑$
a/Theo pt :
$n_{H_2}=1/2.n_{HCl}=1/2.0,8=0,4mol$
$⇒V_{H_2}=0,4.22,4=8,96l$
b/Chưa rõ đề
c/Theo pt :
$ n_{Zn}=n_{ZnCl_2}=1/2.n_{HCl}=1/2.0,8=0,4mol$
$⇒m_{ZnCl_2}=0,4.136=54,4g$
$m_{Zn}=0,4.65=26g$
$m_{ddspu}=26+200-0,4.2=225,2g$
$⇒C\%_{ZnCl_2}=\dfrac{54,4}{225,2}.100\%=24,16\%$