Đáp án:
`x=15`
Giải thích các bước giải:
Có `A=7/114;B=5/114`
`=>B/A=(5/114)/(7/114)=5/114 .114/7=5/7`
Mà `((28 3/7-27 5/9)(2^26+5.4^12))/(8^8.(x-4))=B/A`
`=>((28 3/7-27 5/9)(2^26+5.4^12))/(8^8.(x-4))=5/7`
`=>(55/63.(2^24. 2^2+5.(2^2)^12))/((2^3)^8.(x-4))=5/7`
`=>(55/63.(2^24. 4+5.2^24))/(2^24.(x-4))=5/7`
`=>(55/63. 2^24.( 4+5))/(2^24.(x-4))=5/7`
`=>(55/63. 2^24. 9)/(2^24.(x-4))=5/7`
`=>(2^24. 55/7)/(2^24.(x-4))=5/7`
`=>(55/7)/(x-4)=5/7`
`=>55/7 .7 =5(x-4)`
`=>55=5x-20`
`=>5x=55+20=75`
`=>x=15.`
Vậy `x=15`.
