$|2x-3|=|3x+4|$
$⇔\left[ \begin{array}{l}2x-3=3x+4\\2x-3=-3x-4\end{array} \right.⇔\left[ \begin{array}{l}x=-7\\x=\frac{-1}{5}\end{array} \right.$
Vậy $x=-7,x=\frac{-1}{5}$
$|5-3x|=x+1$ $Đk:x≥-1$
$⇒|5-3x|=|x+1|$
$⇔\left[ \begin{array}{l}5-3x=x+1\\5-3x=-x-1\end{array} \right.⇔\left[ \begin{array}{l}x=1\ (tm)\\x=3\ (tm)\end{array} \right.$
Vậy $x=1,x=3$.