`E = 4x^2 + 4x + 8`
`E = (2x)^2 + 2 . 2x + 1 + 7`
`E = (2x + 1)^2 + 7`
$\text{Có: $(2x + 1)^2$ ≥ 0 ∀ x}$
$\text{⇒ $(2x + 1)^2$ + 7 ≥ 7 ∀ x}$
$\text{Dấu "=" xảy ra}$
`⇔ (2x + 1)^2 = 0`
`⇔ 2x + 1 = 0`
`⇔ 2x = -1`
`⇔ x = -1/2`
$\text{Vậy Min E = 7 nếu x = $\dfrac{-1}{2}$}$