The width of the garden is:
x.$\frac{1}{3}$ -5(dm)
Because the area is 252 dm2,so:
x.(x.$\frac{1}{3}$-5)=252($dm^{2}$ )
⇒$x^{2}$ .$\frac{1}{3}$-x.5=252
⇒x=36 dm
The width of the garden is:
36.$\frac{1}{3}$-5=125(cm)
⇒125 cm=12,5 dm
The perimeter of this garden is
36.12,5=450(dm)
Answer:450 dm