Đáp án: $12-12\sqrt{2}+16\sqrt{3}$
Giải thích các bước giải:
Ta có:
$(\sqrt{6}-2\sqrt{3}+5\sqrt{2}-\dfrac12\sqrt{8})\cdot 2\sqrt{6}$
$=(\sqrt{6}-2\sqrt{3}+5\sqrt{2}-\dfrac12\cdot 2\sqrt{2})\cdot 2\sqrt{6}$
$=(\sqrt{6}-2\sqrt{3}+5\sqrt{2}-\sqrt{2})\cdot 2\sqrt{6}$
$=(\sqrt{6}-2\sqrt{3}+4\sqrt{2})\cdot 2\sqrt{6}$
$=2\sqrt{6}\sqrt{6}-2\cdot \:2\sqrt{6}\sqrt{3}+2\cdot \:4\sqrt{6}\sqrt{2}$
$=12-12\sqrt{2}+16\sqrt{3}$
