Đáp án:

 $a) x=\dfrac{13}{12}\\
b)
x=\dfrac{-2}{3}\\
c)
x=-12\\
d)
x=\dfrac{192}{5}\\
e)
x=\dfrac{3}{20}\\
g)
 x=0\\
h)
 x=\pm 3,5\\
i)
 {\left[\begin{aligned}x=10\\x=-20\end{aligned}\right.}\\
m)
 {\left[\begin{aligned} x =\dfrac{67}{12}\\ x =-\dfrac{85}{12}\end{aligned}\right.}\\
n)
 {\left[\begin{aligned}x=\dfrac{12}{5}\\x=\dfrac{-8}{5}\end{aligned}\right.}\\$

Giải thích các bước giải:

 $a) x+\dfrac{1}{4}=\dfrac{4}{3}\Rightarrow x=\dfrac{4}{3}-\dfrac{1}{4}\\
x=\dfrac{16}{12}-\dfrac{3}{12}\Rightarrow x=\dfrac{13}{12}\\
b)
\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{29}{60}\\
\Leftrightarrow \dfrac{2}{5}x=\dfrac{29}{60}-\dfrac{3}{4}\\
\Leftrightarrow \dfrac{2}{5}x=\dfrac{29}{60}-\dfrac{45}{60}\\
\Leftrightarrow \dfrac{2}{5}x=\dfrac{-16}{60}\\
\Leftrightarrow x=\dfrac{-16}{60}.\dfrac{5}{2}=\dfrac{-2}{3}\\
c)
\dfrac{-12}{13}x-5=6\dfrac{1}{13}\\
\Leftrightarrow \dfrac{-12}{13}x=\dfrac{79}{13}+5\\
\Leftrightarrow \dfrac{-12}{13}x=\dfrac{79}{13}+\dfrac{65}{13}\\
\Leftrightarrow \dfrac{-12}{13}x=\dfrac{144}{13}\\
\Leftrightarrow x=\dfrac{144}{13}.\dfrac{13}{-12}=-12\\
d)
\dfrac{x}{16}=\dfrac{12}{5}\\
\Leftrightarrow x=\dfrac{12}{5}.16=\dfrac{192}{5}\\
e)
\dfrac{11}{12}-\dfrac{2}{5}+x=\dfrac{2}{3}\\
\Leftrightarrow x=\dfrac{2}{3}-\dfrac{11}{12}+\dfrac{2}{5}\\
\Leftrightarrow x=\dfrac{40}{60}-\dfrac{55}{60}+\dfrac{24}{60}\\
\Leftrightarrow x=\dfrac{9}{60}=\dfrac{3}{20}\\
g)
2x.(-\dfrac{1}{7})=0\\
\Leftrightarrow x=0\\
h)
|x|-2,2=1,3\\
\Leftrightarrow |x|=1,3+2,2=3.5\\
\Leftrightarrow x=\pm 3,5\\
i)
|x+5|-6=9\\
\Leftrightarrow |x+5|=9+6=15\\
\Leftrightarrow {\left[\begin{aligned}x+5=15\\x+5=-15\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned}x=10\\x=-20\end{aligned}\right.}\\
m)
\left | x+\dfrac{3}{4} \right |-\dfrac{1}{3}=6\\
\Leftrightarrow \left | x+\dfrac{3}{4} \right |=6+\dfrac{1}{3}\\
\Leftrightarrow \left | x+\dfrac{3}{4} \right |=\dfrac{18}{3}+\dfrac{1}{3}\\
\Leftrightarrow \left | x+\dfrac{3}{4} \right |=\dfrac{19}{3}\\
\Leftrightarrow {\left[\begin{aligned} x+\dfrac{3}{4} =\dfrac{19}{3}\\ x+\dfrac{3}{4} =-\dfrac{19}{3}\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned} x =\dfrac{19}{3}-\dfrac{3}{4}\\ x =-\dfrac{19}{3}-\dfrac{3}{4}\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned} x =\dfrac{76}{12}-\dfrac{9}{12}\\ x =-\dfrac{76}{12}-\dfrac{9}{12}\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned} x =\dfrac{67}{12}\\ x =-\dfrac{85}{12}\end{aligned}\right.}\\
n)
\left | x-\dfrac{2}{5} \right |+\dfrac{3}{4}=\dfrac{11}{4}\\
\Leftrightarrow \left | x-\dfrac{2}{5} \right |=\dfrac{11}{4}-\dfrac{3}{4}\\
\Leftrightarrow \left | x-\dfrac{2}{5} \right |=\dfrac{8}{4}=2\\
\Leftrightarrow {\left[\begin{aligned}x-\dfrac{2}{5}=2\\x-\dfrac{2}{5}=-2\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned}x=2+\dfrac{2}{5}\\x=-2+\dfrac{2}{5}\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned}x=\dfrac{10}{5}+\dfrac{2}{5}\\x=\dfrac{-10}{5}+\dfrac{2}{5}\end{aligned}\right.}\\
\Leftrightarrow {\left[\begin{aligned}x=\dfrac{12}{5}\\x=\dfrac{-8}{5}\end{aligned}\right.}\\$