Đáp án:
Giải thích các bước giải:
Ta có:
$\dfrac{4^6. 9^5+ 6^{9. 120}}{8^4. 3^{12}- 6^{11}}$
$=\dfrac{(2^2)^6. (3^2)^5+ (2. 3)^9. 2^3. 3. 5}{(2^3)^4. 3^{12}- (2. 3)^{11}}$
$= \dfrac{2^{12}. 3^{10}+ 2^{9}. 3^{9}+ 2^{3}. 3. 5}{2^{12}. 3^{12}- 2^{11}. 3^{11}}$
$= \dfrac{2^{12}. 3^{10}+ 2^{12}. 3^{10}. 5}{2^{11}. 3^{11}. (2. 3- 1)}$
$= \dfrac{2^{12}. 3^{10}. (1+ 5)}{2^{11}. 3^{11}. 5}$
$= \dfrac{2. 6}{5. 3}= \dfrac{12}{15}$
$= \dfrac{4}{5}$
