Đáp án:
$1)\dfrac{5}{2}(x-y)^3\\
2)
18(x+y)\\
3)
\dfrac{1}{3}(x+y-z)^2\\
4)
5(x-y-z)^2\\
5)
\dfrac{1}{2}x(8x^5+1)\\
6)
-3x^2(2x^2-x+3)\\
7)
y(-3x^2y^3+2x-y)$
Giải thích các bước giải:
$1)\dfrac{5(x-y)^5}{2(x-y)^2}=\dfrac{5}{2}(x-y)^3\\
2)
\dfrac{36(x+y)^3}{2(x+y)^2}=18(x+y)\\
3)
\dfrac{4(x+y-z)^5}{12(x+y-z)^3}=\dfrac{1}{3}(x+y-z)^2\\
4)
\dfrac{35(x-y-x)^7}{7(x-y-z)^5}=5(x-y-z)^2\\
5)
\dfrac{8x^4x^3+x^2}{2x}\\
=\dfrac{x^2(8x^5+1)}{2x}\\
=\dfrac{1}{2}x(8x^5+1)\\
6)
\dfrac{2x^4-x^3+3x^2}{-\dfrac{1}{3}x^2}\\
=\dfrac{x^2(2x^2-x+3)}{-\dfrac{1}{3}x^2}\\
=-3x^2(2x^2-x+3)\\
7)
\dfrac{-18x^3y^5+12x^2y^2-6xy^3}{6xy}\\
=\dfrac{6xy^2(-3x^2y^3+2x-y)}{6xy}\\
=y(-3x^2y^3+2x-y)$
