Đáp án:
$1011$
Giải thích các bước giải:
Đặt $A=\dfrac{2009×2010+2011×12+1998}{2011×2010-2010×2009}$
$⇒A=\dfrac{2009×2010+(2010+1)×12+1998}{2010×(2011-2009)}$
$⇒A=\dfrac{2009×2010+2010×12+12+1998}{2010×2}$
$⇒A=\dfrac{2009×2010+2010×12+2010}{2010×2}$
$⇒A=\dfrac{2010×(2009+12+1)}{2×2010}$
$⇒A=\dfrac{2022}{2}=1011$